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Print alphabet pattern ‘u’

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Print alphabet pattern ‘x’¶

Print alphabet pattern ‘x’.

Expected output:
 0123456
0 *   *
1 *   *
2  * *
3   *
4  * *
5 *   *
6 *   *
result_str = ""

for row in range(0, 7):
    for column in range(0, 7):
        if (((column == 1 or column == 5) and
             (row > 4 or row < 2)
            ) or
            row == column and
            column > 0 and column < 6 or
            (column == 2 and row == 4) or
            (column == 4 and row == 2)
           ):
            result_str += "*"
        else:
            result_str += " "

    result_str += "\n"

print(result_str)

Output:

*   *
*   *
 * *
  *
 * *
*   *
*   *

See also

https://www.w3resource.com/python-exercises/python-conditional-exercise-29.php

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